If `x=sqrt6+sqrt5` then `x^2+1/x^2-2=`

If x=sqrt6+sqrt5 then find x^2+1/x^2-2

If sqrt(x)+(1)/(sqrt(x)) =sqrt(6) , then x^(2)+(1)/(x^(2)) is equal to :

If x=(sqrt5)+1 and y=(sqrt5)-1 , then what is the value of (x^2//y^2)+ (y^2//x^2) + 4[(x//y) + (y//x)] + 6 ?

If sqrtx= sqrt3-sqrt5 , then the value of x^2-16x+6 is : यदि sqrtx= sqrt3-sqrt5 , x^2-16x+6 का मान ज्ञात करें :

If x=5+2sqrt(6), then sqrt((x)/(2))-(1)/(sqrt(2x))= (a) 1 (b) 2 (c) 3 (d) 4