Write the domain of the relation R defined on the set Z of integers as follows `(a,b) in R <=> a^2+b^2=25`

Write the domain of the relation R defined on the set Z of integers as follows: (a,b)in R hArr a^(2)+b^(2)=25

Write the domain of the relation R defined on the set Z of integers as follows (a,b)in R hArr a^(2)+b^(2)=25

Write the domain of the relation R defined on the set Z of integers as follows: (a ,\ b) in RhArra^2+b^2=25

If a relation R is defined on the set Z of integers as follows (a,b)in R iff a^(2)+b^(2)=25 then, domain ( R ) =

If a relation R is defined on the set Z of integers as following (a,b) inR iff a^2+b^2=25 , then find domain R.

Write the domain of the relation R (a,a),(a,b),(a,c) defined on the set (a,b,c)

A relation R is defined on the set z of integers as follows : (x,y) in RR hArr x^(2) +y^(2) = 25 . Express R and R^(-1) as the set of ordered pairs and hence find their respective domains.

A relation R is defined on the set Z of integers as follows. R ={ (x, y) in R: x^2+y^2=2 5} Express R and R^-1 as the sets of ordèred pairs and hence find their respective domains.

Prove that the relation R defined on the set Z of integers as R= {(a, b) : 4 divides abs(a-b)} is an equivalence relation.