`tan2 0^(@)+2tan5 0^(@)=`

The value of (tan7 0^0-tan2 0^0)/(tan5 0^0)=

Evaluate : (2sin68^(0))/(cos22^(0))-(2cot15^(0))/(5tan75^(0))-(3tan45^(0)tan20^(@)tan40^(@)tan50^(@)tan70^(@))/(5)

S o l v e(sin1 0^(@))^(tanx+tan3x)=tan1 5^(@)+tan3 0^(@)+tan1 5^(@)tan3 0^(@), x in (0,pi]

The general solution of the equation tan(x+20^@)tan(x-4 0^(@))=tan(x-2 0^(@))tan(x+4 0^(@)) is

The value of tan1^(0)tan2^(0)tan3^(@)tan89^(@) is 0b.1 c.1/2d .not defined

Show that tan1^(0)tan2^(0)...tan89^(@)=1

(2tan3 0^(@))/(1-tan^2 3 0^(@))

(2tan3 0^(@))/(1-tan^2 3 0^(@))

The value of tan203^(@)+tan22^(0)+tan203^(0)tan22^(0) is (A)-1 (B) 0(C)1(D)2

lim_ (x rarr0) log_ (tan ^ (2) x) tan ^ (2) 2x