Select the rate law that corresponds to the datashown for the reaction `A+BtoC`
`{:(,Exp.,[A],[B],Rate),(,1,0.012,0.035,0.10),(,2,0.024,0.070,0.80),(,3,0.024,0.035,0.10),(,4,0.012,0.070,0.80):}`

Select the law that correponds to data shown for the following reaction A+B rarr Products {:(Exp,[A],[B],"Initial rate",),(1,0.012,0.035,0.1,),(2,0.024,0.070,0.8,),(3,0.024,0.035,0.1,),(4,0.012,0.070,0.8,):}

The data for the reaction: A + B overset(k)rarr C . |{:("Experiment",[A]_(0),[B]_(0),"Initial rate"),(1,0.012,0.035,0.10),(2,0.024,0.070,0.80),(3,0.024,0.035,0.10),(4,0.012,0.070,0.80):}| The rate law corresponding to the above data is (a) Rate = k[B]^(3) , (b) Rate = k[B]^(4) ( c) Rate = k[A][B]^(3) , (d) Rate = k[A]^(2)[B]^(2)

The data for the reaction: A + B overset(k)rarr C . |{:("Experiment",[A]_(0),[B]_(0),"Initial rate"),(1,0.012,0.035,0.10),(2,0.024,0.070,0.80),(3,0.024,0.035,0.10),(4,0.012,0.070,0.80):}| The rate law corresponding to the above data is (a) Rate = k[B]^(3) , (b) Rate = k[B]^(4) ( c) Rate = k[A][B]^(3) , (d) Rate = k[A]^(2)[B]^(2)

|{:([A],[B],"Initial Rate"),(0.05,0.05,0.045),(0.10,0.05,0.09),(0.20,0.10,0.72):}| for 2A+BtoC . Find the rate law

|{:([A],[B],"Initial Rate"),(0.05,0.05,0.045),(0.10,0.05,0.09),(0.20,0.10,0.72):}| for 2A+BtoC . Find the rate low

(a) Write the rate expression. (b) Find the rate constant for {:([A]_(0),[B]_(0),,," R_(0) "Rate" (mol litre^(-1) s^(-1))),(0.1,0.2,,,0.05),(0.2,0.2,,,0.10),(0.1,0.1,,,0.05):}

For a reaction : A+B rarr Products the rate of the reaction of various concentrations are given below : {:("Expt No.",[A], [B]," ""Rate (mol dm"^(-3)s^(-1)),(1,0.2,0.2," "2),(2,0.2,0.4," "4),(3,0.6,0.4," "36):} The rate law for the above reaction is :

Simplify (0.12**(0.0104-0.002)+0.36*0.002)/(0.12*0.12)