[" A normal is drawn at a point "P(x,y)" of a curve.It meets the "x" -axis at "Q." If "PQ" is "],[" of constant length "k," and the curve passes through "(0,k)," then the equation of "],[" the curve is "]

A normal is drawn at a point P(x,y) of a curve It meets the x-axis at Q If PQ is of constant length k such a curve passing through (0,k) is

A normal is drawn at a point P(x,y) of a curve. It meets the x-axis at Q such that PQ is of constant length k . Answer the question:If the curve passes through the point (0,k) , then its equation is (A) x^2-y^2=k^2 (B) x^2+y^2=k^2 (C) x^2-y^2=2k^2 (D) x^2+y^2=2k^2

A normal is drawn at a point P(x,y) of a curve. It meets the x-axis at Q such that PQ is of constant length k . Answer the question:If the curve passes through the point (0,k) , then its equation is (A) x^2-y^2=k^2 (B) x^2+y^2=k^2 (C) x^2-y^2=2k^2 (D) x^2+y^2=2k^2

A normal is drawn at a point P(x,y) of a curve. It meets the x-axis at Q such that PQ is of constant length k . Find coordinates of q also find equation of curve

A normal is drwn at a point P(x,y) of a curve. It meets the x-axis at Q. If PQ is of constant length k, then show that the differential equation describing such curves is y(dy)/(dx)=+-sqrt(k^(2)-y^(2)) . Find the equation of such a curve passing through (0,k).

A normal is drawn at a point P(x,y) of a curve. It meets the x-axis at Q such that PQ is of constant length k . Answer the question:The differential equation describing such a curve is (A) y dy/dx=+-sqrt(k^2-x^2) (B) x dy/dx=+-sqrt(k^2-x^2) (C) y dy/dx=+-sqrt(k^2-y^2) (D) x dy/dx=+-sqrt(k^2-y^2)

A normal is drawn at a point P(x,y) of a curve. It meets the x-axis at Q such that PQ is of constant length k . Answer the question:The differential equation describing such a curve is (A) y dy/dx=+-sqrt(k^2-x^2) (B) x dy/dx=+-sqrt(k^2-x^2) (C) y dy/dx=+-sqrt(k^2-y^2) (D) x dy/dx=+-sqrt(k^2-y^2)

A normal is drawn at a point P(x,y) of a curve.It meets the x-axis at Q. If PQ has constant length k, then show that the differential equation describing such curves is y(dy)/(dx)=+-sqrt(k^(2)-y^(2)). Find the equation of such a curve passing through (0,k).