`4 sin(pi/6)sin^2(pi/3)+3cos(pi/3)tan(pi/4)+cose^2(pi/2)=2sec^2(pi/4)`

sin (pi/2) = 2 sin(pi/4) cos (pi/4)

sin^(2) (pi/6)+cos^(2) (pi/3)-tan^(2) (pi/4)=-1/2

sin^(2)pi/6+cos^(2)pi/3-tan^(2)pi/4=-1/2

sin^2 pi/6 +cos^2 pi/3 -tan^2 pi/4=-1/2

Prove that sin^2(pi/6)+cos^2(pi/3)-tan^2(pi/4)=-1/2

2sin^2 pi/6 +cose c^2 (7pi)/6 cos^2 pi/3=3/2

sin ^(2)(pi/6) + cos ^(2)(pi/3) - tan ^(2)(pi/4) =- 1/2

2sin^2 (3pi)/4 +2cos^2 pi/4 +2sec^2 pi/3=10

Evaluate sin^2(pi/4)+sin^2 (3pi/4)+sin^2(5pi/4)+sin^2(7pi/4)

Prove that (i) " tan"^(2) .(pi)/(3) + 2cos^(2) .(pi)/(4)+ 3 sec^(2).(pi)/(6)+ 4 cos^(2).(pi)/(2)=8 (ii) " sin ".(pi)/(6) " cos 0 + sin ".(pi)/(4) " cos " .(pi)(4) + " sin " .(pi)/(3) "cos " .(pi)/(6) =(7)/(4) (iii) " 4sin " (pi)/(6) " sin"^(2) (pi)/(3) + 3 " cos " .(pi)/(3) " tan ".(pi)/(4) = " cosec"^(2).(pi)/(2)=4