[" If "a=cos alpha+i sin alpha,b=cos beta+i sin beta],[c=cos gamma+i sin gamma" and "b/c+c/a+a/b=1," then "],[cos(beta-gamma)+cos(gamma-alpha)+cos(alpha-beta)" is equal "],[" to "]

If a=cos alpha+i sin alpha, b=cos beta+isin beta,c=cos gamma+i sin gamma and b/c+c/a+a/b=1, then cos(beta-gamma)+cos(gamma-alpha)+cos(alpha-beta)=

If alpha=cos alpha+i sin alpha,b=cos beta+i sin beta,c=cos gamma+i sin gamma and (b)/(c)+(c)/(a)+(a)/(b)=1 then cos(beta-gamma)+cos(gamma-alpha)+cos(alpha-beta)=

If a =cos alpha - i sin alpha, b= cos beta - i sin beta, c = cos gamma - i sin gamma , then ((a^2c^2 - b^2)/(abc)) is …………..

If origin is the orthocentre of the triangle with vertices A(cos alpha,sin alpha),B(cos beta,sin beta),C(cos gamma,sin gamma) then cos(2 alpha-beta-gamma)+cos(2 beta-gamma-alpha)+cos(2 gamma-alpha-beta)=

cos alpha sin (beta-gamma)+cos beta sin (gamma-alpha) +cos gamma(sin alpha-beta)=

If a=cis alpha , b= cis beta , c= cis gamma and (a)/(b)+(b)/(c)+(c)/(a)=1 then cos (alpha-beta)+cos (beta-gamma)+cos (gamma-alpha)=

cos alpha sin (beta-gamma) + cos beta sin (gamma-alpha) + cos gamma sin (alpha-beta) =

cos alpha sin (beta-gamma)+cos betasin (gamma-alpha+cos gamma sin (alpha-beta)=