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[" 22.Calcium hydroxide is a strong base...

[" 22.Calcium hydroxide is a strong base.Compute "[Ca^(2+)]" and "[OH^(-)]" for a solution that is prepared "],[" by dissolving "0.60g" of "Ca(OH)_(2)" in enough water to make a "1500mL" of solution."],[" [Atomic mass: "Ca=40,0=16,H=1]],[[" (a) "5.4times10^(-3),9.1times10^(-13)," (b) "5.4times10^(-3),1.08times10^(-2)],[" (c) "5.4times10^(-3),5.4times10^(-3)," (d) "8.1times10^(-3),8.1times10^(-3)]]

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Calcium hydroxide is a strong base. Compute [Ca^(2+)] and [OH^(-)] "for" a solution that is prepared by dissolving 0.60 g of Ca(OH)_(2) in enough water to make a 1500 mL of solution. [Atomic mass : Ca=40, O=16, H=1 ]

Calcium hydroxide is a strong base. Compute [Ca^(2+)] and [OH^(-)] "for" a solution that is prepared by dissolving 0.60 g of Ca(OH)_(2) in enough water to make a 1500 mL of solution. [Atomic mass : Ca=40, O=16, H=1 ]

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