If `r_1` and `r_2` are lengths of perpendicular chords of the parabola drawn through vertex then` (r_1r_2)^(4/3)` is

Show that if r_1 and r_2 be the lengths of perpendicular chords of a parabola drawn through the vertex, then (r_1 r_2)^(4/3) = 16a^2 (r_1^(2/3) + r_2^(2/3))

If r_(1) and r_(2) are the lengths of perpendicular chords of the parabola y^(2)=4ax drawn through the vertex,then (r_(1)r_(2))^((4)/(3))

If r_1 and r_2 be the length sof perpendicular chords of a parabola y^2 = 4x through its vertex, then (r_1 r_2)^(4/3)/(r_1^(2/3) + r_2^(2/3) =

If r_(1), r_(2) be the length of the perpendicular chords of the parabola y^(2) = 4ax drawn through the vertex, then show that (r_(1)r_(2))^(4//3) = 16a^(2)(r_(1)^(2//3) +r_(2)^(2//3))

Prove that r_(1)+r_(2)+r_(3)-r=4R

Prove that r_(1)+r_(2)+r_(3)-r=4R

What is the length of the perpendicular drawn from the centre of circle of radius r on the chord of length sqrt3

Prove that (r_1-r)(r_2-r)(r_3-r)=4R r^2

Prove that (r_1-r)(r_2-r)(r_3-r)=4R r^2

A circle of radius r drawn on a chord of the parabola y^(2)=4ax as diameter touches theaxis of the parabola.Prove that the slope of the chord is (2a)/(r)