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Solve by componendo dividendo method

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`((3x-4)^3-(x+1)^3)/((3x-4)^3+(x+1)^3) = 61/89`
Using componendo and dividendo both sides,
`((3x-4)^3-(x+1)^3+(3x-4)^3+(x+1)^3)/((3x-4)^3-(x+1)^3-(3x-4)^3-(x+1)^3) = (61+189)/(61-189)`
`=>(2(3x-4)^3)/(-2(x+1)^3) = -250/128`
`=>(3x-4)^3/(x+1)^3 = 125/64`
`=>((3x-4)/(x+1))^3 = (5/4)^3`
`=>(3x-4)/(x+1) = 5/4`
`=>12x-16 = 5x+5`
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