The velocity of a particle describing SHM is `16 cm s^(-1)` at a distance of 8 cm from mean position and `8 cm s^(-1)` at a distance of 12 cm from mean postion. Calculate the amplitude of the motion.

A particle is executing simple harmonic motion. The velocity of the particle is 10 m s^(-1) . What at a distance of 5 cm from mean position and 8 cm s^(-1) when at a distance of 12 cm from mean position. What will be the amplitude of motion ?

The acceleration of a particle performing S.H.M. is 12 cm/ s^(2) at a distance of 3 cm from the mean position. Its time period is _____ .

The acceleration of a particle performing SHM is 12cm//s^2 at a distance of 3 cm from the mean position. Calculate its time-period.

The acceleration of a particle performing S.H.M. is 12 cm // sec^(2) cm at a distance of 3 cm form the mean position. Its period is

Calculate the time period of a particle whose acceleration is 5 cm s^(-2) at a distance of 5 cm from the mean posiiton.

A particle executing SHM possesses velocities 20cm*s^(-1)and15cm*s^(-1) at distances 6 cm and 8 cm respectively from its mean position. Calculate the amplitude and the time period of the particle.

The amplitude of a particle executing SHM is 4 cm. At the mean position, the speed of the particle is 16 cm/s. The distance of the particle from the mean position at which the speed of the particle becomes 8sqrt(3) cm/sec will be

A particle is having potential energy 1/3 of the maximum value at a distance of 4 cm from mean position. Amplitude of motion is

The acceleration of a particle performing a linear S.H.M. is 16 cm//s^(2) , when it is at a distance of 4 cm from the mean position. The period of S.H.M. is