Home
Class 11
PHYSICS
For a monoatomic ideal gas undergoing an...

For a monoatomic ideal gas undergoing an adiabatic change, the relation between temperature and volume `TV^(x)` = constant, where x is

Promotional Banner

Similar Questions

Explore conceptually related problems

For a gas undergoing an adiabatic change, the relation between temperature and volume is found to be TV^(0.4) = constant. This gas must be

For a gas undergoing an adiabatic process, the relation between temperature and volume is found to be TV^(@.4) = constant. The gas may be

An ideal gas undergoing adiabatic expansion obeys the relations

An ideal gas undergoing adiabatic change has the following pressure-temperature relationship

An ideal gas undergoing adiabatic change has the following pressure-temperature relationship

A rigid diatomic ideal gas undergoes an adiabatic process at room temperature .The relation between temperature and volume for this process in TV^x = constant ,then x is :

A rigid diatomic ideal gas undergoes an adiabatic process at room temperature .The relation between temperature and volume for this process in TV^x = constant ,then x is :

A rigid diatomic ideal gas undergoes an adiabatic process at room temperature .The relation between temperature and volume for this process in TV^x = constant ,then x is :