Let `ABCDEF` be a regular hexagon and `vec(AB)= veca,vec(BC)= vec b, vec(CD) = vec c` then `vec(AE)` is

Assertion ABCDEF is a regular hexagon and vec(AB)=veca,vec(BC)=vecb and vec(CD)=vecc, then vec(EA) is equal to -(vecb+vecc) , Reason: vec(AE)=vec(BD)=vec(BC)+vec(CD) (A) Both A and R are true and R is the correct explanation of A (B) Both A and R are true R is not te correct explanation of A (C) A is true but R is false. (D) A is false but R is true.

Assertion ABCDEF is a regular hexagon and vec(AB)=veca,vec(BC)=vecb and vec(CD)=vecc, then vec(EA) is equal to -(vecb+vecc) , Reason: vec(AE)=vec(BD)=vec(BC)+vec(CD) (A) Both A and R are true and R is the correct explanation of A (B) Both A and R are true R is not te correct explanation of A (C) A is true but R is false. (D) A is false but R is true.

Let ABCDEF be a regular hexagon and vec AB=vec a,vec BC=vec b,vec CD=vec c then vec AE is

In a regular hexagon ABCDEF, vec(AB)=a, vec(BC)=b and vec(CD) = c. Then, vec(AE) =

If ABCDEF is a regular hexagon with vec(AB) = veca and vec(BC)= vecb, then vec(CE) equals

In a regular hexagon ABCDEF, vec(AE)

In a regular hexagon ABCDEF, vec(AE)

If ABCDEF is a regular hexagon with vec(AB) = vec(a) ,vec(BC ) = vec(b) then vec(CE) equals :

ABCDEF is a regular hexagon. If vec(AB) = vec(a) and vec(BC) = vec(b), " find " vec(CD), vec(DE), vec(EF) and vec(FA) in terms of vec(a) and vec(b)

If ABCDEF is a regular hexagon then vec(AD)+vec(EB)+vec(FC) equals :