The temperature of sink of Carnot engine is `27^(@)C`. Efficiency of engine is `25%`. Then temeperature of source is

The temperature of sink of Carnot engine is 27^(@) C. Efficiency of engine is 25%. Then temperature of source is

The temperature of sink of Carnot engine is 127^@C . Efficiency of engine is 50% . Then, temperature of source is

The temperature of sink of Carnot engine is 27°C. Efficiency of engine is 25%. Then find the temperature of source.

A Carnot engine converts one-sixth of the heat into work. When the temperature of the sink is reduced by 62°C, the efficiency of the engine is doubled. The temperature of the source and sink are

Source temperature of a carnot engine is 127 celsius if efficiency of carnot engine is 60% then find sink temperature

The temperature of the sink of a carnot engine is 300 K and its efficiency is 40 %. Find the decrease in temperature of the sink required to increase the efficiency of the engine to 50% keeping temperature of the source to be constant.

A Carnot engine has an efficiency of 1//6 . When the temperature of the sink is reduced by 62^(@)C , its efficiency is doubled. The temperature of the source and the sink are, respectively.

In a Carnot engine the temperature of source is 1000 K and the efficiency of engine is 70%. What is the temperature of the sink ?