Eccentric angle of one of the points on the ellipse `x^2 + 3 y^2 = 6` at a distance 2 units from the centre of ellipse is `k pi/4`, then k is:

Find the eccentric angle of a point on the ellipse x^2 + 3y^2 = 6 at a distance 2 units from the centre of the ellipse.

Eccentric angle of a point on the ellipse x^(2)+3 y^(2)=6 at a distance 2 units from the centre of the ellipse is

Eccentric angle of a point on the ellipse x^(2)/4+y^(2)/3=1 at a distance 2 units from the centre of ellipse is:

The eccentric angle of a point on the ellipse x^(2)/6 + y^(2)/2 = 1 whose distance from the centre of the ellipse is 2, is

The eccentric angle of a point on the ellipse x^(2)/6 + y^(2)/2 = 1 whose distance from the centre of the ellipse is 2, is

The eccentric angle of a point on the ellipse x^(2)/6 + y^(2)/2 = 1 whose distance from the centre of the ellipse is 2, is

The eccentric angle of a point on the ellipse x^(2)/6 + y^(2)/2 = 1 whose distance from the centre of the ellipse is 2, is

The eccentric angle of a point on the ellipse x^2/6 + y^2/2 = 1 whose distance from the centre of the ellipse is 2, is (A) pi/4 (B) 7pi/6 (C) 3pi/2 (D) 5pi/3