[" Heat of neurtalisation of oxalic acid is - "106.7KJmol^(-1)" using NaOH hence "Delta H" of : "],[H_(2)C_(2)O_(4)rarr C_(2)O_(4)^(2-)+2H^(+)" is : "]

Heat of neutralisation of oxalic acid is -106.7 KJ mol^(-1) using NaOH hence Delta H of : H_(2)C_(2)O_(4)rarr C_(2)O_(4)^(2-)+2H^(+) is :-

Heat of neutralisation of oxalic acid is -106.7 KJ mol^(-1) using NaOH hence Delta H of : H_(2)C_(2)O_(4)rarr C_(2)O_(4)^(2-)+2H^(+) is :-

Heat of neutralisation of oxalic acid is -106.7 kJ mol^-1 using NaOH. Hence DeltaH of H_2C_2O_4 iff C_2O_4^(2-) +2H^+ is

Heat of neutralisation of oxalic acid is -53.35 kJ/g.eq. using NaOH. Calculate the value of Detla H for the given reaction H_(2)C_(2)O_(4) hArr C_(2)O_(4)^(2-) + 2H^(+)

The heat of neutralisation of oxalic acid is -25.4 kcal mol^(-1) using strong base, NaOH . Hence, the enthalpy change of the process is H_(2)C_(2)O_(4) hArr 2H^(o+) +C_(2)O_(4)^(2-) is

The heat of neutralisation of oxalic acid is -25.4 kcal mol^(-1) using strong base, NaOH . Hence, the enthaly change of the process is H_(2)C_(2)O_(4) hArr 2H^(o+) +C_(2)O_(4)^(2-) is

Heat of neutralization between HCl and NaOH is -13.7 kcal "equiv"^(–1) . Heat of neutralization of H_2C_2O_4 (oxalic acid) with NaOH is -26 kcal mol^(-1) . Hence, heat of dissociation of H_(2)C_(2)O_(4) as H_2C_2O_(4) rarr 2H^(+) + C_(2)O_(4)^(2-) , is :

Heat of neutralization between HCl and NaOH is -13.7 kcal "equiv"^(–1) . Heat of neutralization of H_2C_2O_4 (oxalic acid) with NaOH is -26 kcal mol^(-1) . Hence, heat of dissociation of H_(2)C_(2)O_(4) as H_2C_2O_(4) rarr 2H^(+) + C_(2)O_(4)^(2-) , is :