[" The correct order of stability of given catanions will be ",],[CH_(3)-CH_(2),CH_(2)=CH,HC=C],[(I),(II),(III)]

The correct order of stability of given carbocations is (i) NO_(2)—CH_(2)—CH_(2)^(+) (ii) NH_(2)—CH_(2)—CH_(2)^(+) (iii) CH_(3)—O—CH_(2)^(+) (iv) HO—CH_(2)^(+) (v) NH_(2)—CH_(2)^(+) (vi) NO_(2)—CH_(2)^(+) (vii) CH_(3)O—CH_(2)—CH_(2)^(+)

The correct order of stability of given carbocations is (i) NO_(2)—CH_(2)—CH_(2)^(+) (ii) NH_(2)—CH_(2)—CH_(2)^(+) (iii) CH_(3)—O—CH_(2)^(+) (iv) HO—CH_(2)^(+) (v) NH_(2)—CH_(2)^(+) (vi) NO_(2)—CH_(2)^(+) (vii) CH_(3)O—CH_(2)—CH_(2)^(+)

Which is the correct increasing order of the stability of isomers of pentene ? CH_(3)-CH_(2)-CH_(20=CH_(2)

The order of decreasing stability of the carbanions : (CH_(3))_(3)C^(-)(I),(CH_(3))_(2)CH^(-)(II), CH_(3)CH_(2)^(-)(III), C_(6)H_(5)CH_(2)^(-)(IV) is

The correct order of basicities of the following compounds is - (I) , (II) CH_(3)CH_(2)NH_(2) : (III) (CH_(3))_(2)NH , (IV) CH_(3)-overset(O)overset(||)C-NH_(2))

Which order is correct regarding stability of intermediates. (I) CH_(3)-CH_(2)^-," (II) "CH_(2)=CH^-" (III) "CH equiv C^-