((cos theta+i sin theta)^(4))/((sin theta+(1cos theta)^(5))=sin9 theta-i cos90

(sin theta+i cos theta)^(9) =

((cos theta-i sin theta)^(4))/((sin theta+i cos theta)^(5)) is equal to

((cos theta+i sin theta)^(4))/(((sin theta+i cos theta))^(5)) is equal to

((cos theta+i sin theta)^(4))/((sin theta+i cos theta)^(5)) is equal to.

((cos theta+i sin theta)/(sin theta+i cos theta))^(4)=

([cos theta+i sin theta)/(sin theta+i cos theta))^(4)=?

If ((1+cos theta+i sin theta)/(sin theta+i+i cos theta))^(4)=cos n theta+i sin n theta , then n=

In the form of A+iBz=(cos2 theta+i sin2 theta)^(-5)(cos3 theta-i sin3 theta)^(6)(sin theta-i cos theta)^(3) is

Express the following in a+ib form: ((cos2 theta-i sin2 theta)^(4)(cos4 theta+i sin4 theta)^(-5))/((cos3 theta+i sin3 theta)^(-2)(cos3 theta-i sin3 theta)^(-9))