a=(b-c)sec theta," P.T "tan theta=(2sqrt(bc))/(b-c)sin(A)/(2)

In Delta ABC if a=(b-c)sec theta then (2sqrt(bc))/(b-c)sin((A)/(2))=

In Delta ABC if a=(b-c)sec theta then (2sqrt(b)c)/(b-c)sin((A)/(2))=

If a=(b-c)Sec theta , Prove that tan theta=(2sqrt(bc))/(b-c)Sin(A)/(2)

In DeltaABC if a=(b-c)Sec theta then (2sqrt(bc))/(b-c)"Sin"(A)/(2)=

If a=(b+c)cos theta then show that sin theta=(2sqrt(bc))/(b+c)cos((A)/(2))

If a= ( b-c) sec theta " then " tan theta =

If a = (b-c) "sec" theta , then prove that tan theta = (2sqrt(bc))/(b-c) sin A/2 .

If sin theta = a/(b+c) then show that cos theta = (2sqrt(bc))/(b+c) cos ((A)/(2))

If the three side of a triangle be a, b, c and tan theta=(2 sqrt(ab))/(a-b) "sin"(C)/(2) , then show that "sec" theta =(c)/(a-b) .