[(x)/(2)+y=0.8],[(7)/(x+(y)/(2))=10]

solve using ellimination method (x)/(2)+y=0.8 and (7)/(x)+(y)/(2)=10

The circles whose equations are x^(2)+y^(2)+10x-2y+22=0 and x^(2)+y^(2)+2x-8y+8=0 touch each other. The circle which touch both circles at, the point of contact and passing through (0,0) is, 1) 9(x^(2)+y^(2))-15x-20y=0, 2) 5(x^(2)+y^(2))-18x-80y=0 3) 7(x^(2)+y^(2))-18x-80y=0, 4) x^(2)+y^(2)-9x-40y=0 ]]

(x + y) ^ (10) = x ^ (8) y ^ (2)

Find the equation of the common tangent of the following circles at their point of contact x^(2)+y^(2)=10x-2y+22=0, x^(2)+y^(2)+2x=8y+8=0

Solve [2x+3y-7=0],[3x+2y-8=0]

. The centres of the circles x^(2)+y^(2)-6x-8y-7=0 and x^(2)+y^(2)-4x-10y-3=0 are the ends of the diameter of the circle

If the circles x^(2)+y^(2)+10x+8y+c=0 and x^(2)+y^(2)-10x-8y+c=0 cut onbogonally,then the value of 'C'' is