A series AC circuit contains an inductor `(20 mH)`, a capacitor `(100 muF)`, a resistor `(50 Omega)` and an AC source of `12 V, 50 Hz`. Find the energy dissipated in the circuit in `1000 s`.

A series AC circuit containing an inductor (20 mH), a capacitor (120 mu F ) and a resistor ( 60 Omega ) is driven by an Ac source of 24 V/50Hz. The energy dissipated in the circuit in 60 s is :

A series AC circuit containing an inductor (20 mH), a capacitor (120 mu F ) and a resistor ( 60 Omega ) is driven by an Ac source of 24 V/50Hz. The energy dissipated in the circuit in 60 s is :

An inductor 20xx10^(-3) a capacitor 100(mu)F and a resistor 50 Omega are connected in series across a source of emf V=10 sin 314 t . Then the energy dissipated in the circuit in 20 mim is

An inductor 20xx10^(-3) a capacitor 100(mu)F and a resistor 50 Omega are connected in series across a source of emf V=10 sin 314 t . Then the energy dissipated in the circuit in 20 mim is

An inductor 20 mH , a capacitor 100 muF and a resistor 50 Omega are connected in series across a source of emf, V=10 sin 314 t . The power loss in the circuit is

An inductor 20mH, a capacitor 100muF and a resistor 50Omega are connected in series across a source of emf V=10sin314t. The power loss in the circuit is

An inductor 20 mH , a capacitor 100muF and a resistor 50Omega are connected in series across a source of emf V=10sin314t . The power loss in the circuit is

An inductor 20 mH , a capacitor 100muF and a resistor 50Omega are connected in series across a source of emf V=10sin314t . The power loss in the circuit is