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1). sum(r=0)^n (-1)^r ( "^(n+1)c(r+1) ...

1). `sum_(r=0)^n (-1)^r `(` "^(n+1)c_(r+1) `)/(` "^(r+2)c_(r+1)`) is equal to : (2). if` (x+1)(x+2)(x+3).......(x+n)=A_0+A_1x+A_2x^2+......+A_nx^n `then`A_1+2A_2+3A_3+......+nA_n` is equal to

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