`5` different balls are placed in `5` different boxes randomly. Find the probability that exactly two boxes remain empty. Given each box can hold any number of balls.

Five different marbles are placed in 5 different boxes randomly. Then the probability that exactly two boxes remain empty is (each box can hold any number of marbles) 2//5 b. 12//25 c. 3//5 d. none of these

Five different marbles are placed in 5 different boxes randomly. Then the probability that exactly two boxes remain empty is (each box can hold any number of marbles) 2//5 b. 12//25 c. 3//5 d. none of these

Five different marbles are placed in 5 different boxes randomly.Then the probability that exactly two boxes remain empty is (each box can hold any number of marbles 2/5 b.12/25 c.3/5 d.none of these

Five different marbles are placed in 5 different boxes randomly. Then the probability that exactly two boxes remain empty is (each box can hold any number of marbles) 2//5 b. 12//25 c. 3//5 d. none of these

If 5 different things are placed at random in 3 different boxes then the probability of placing them such that no box remains empty is

If 10 different balls are to be placed in 4 distinct boxes at random, then the parobability that two of these boxes contain exactly 2 and 3 balls is :

If 10 different balls are to be placed in 4 distinct boxes at random, then the parobability that two of these boxes contain exactly 2 and 3 balls is :

Six different balls are put in three different boxes,no box being empty.The probability of putting balls in the boxes in equal numbers is

Six different balls are put in three different boxes, no box being empty. The probability of putting balls in the boxes in equal numbers is

Five balls are to be placed in three boxes in how many diff. ways can be placed the balls so that no box remain empty if .