The phase difference between two `SHM y_(1) = 10 sin (10 pi t + (pi)/(3))` and `y_(2) = 12 sin (8 pi t + (pi)/(4))`to `t = 0.5s` is

Find the phase difference betwee the two progressive wave. y_(1)=A sin ((2pi)/(T) t-(2pi)/(lambda) x) and y_(2)=A cos ((2pi)/(T) t-(2pi)/(lambda)x)

Determine the resultant of two waves given by y_(1) = 4 sin(200 pi t) and y_(2) = 3 sin(200 pi t + pi//2) .

Determine the resultant of two waves given by y_(1) = 4 sin(200 pi t) and y_(2) = 3 sin(200 pi t + pi//2) .

Two simple harmonic motions are represented by the equations y_(1) = 10 sin (3pit + (pi)/(4)) and y_(2) = 5 (3 sin 3 pi t+sqrt(3) cos 3 pi t) . Their amplitudes are in the ratio of

Two S.H.Ms are given by y_(1) = a sin ((pi)/(2) t + (pi)/(2)) and y_(2) = b sin ((2pi)/(3) t + (pi)/(2)) . The phase difference between these after 1 second is

Two S.H.Ms are given by y_(1) = a sin ((pi)/(2) t + (pi)/(2)) and y_(2) = b sin ((2pi)/(3) t + (pi)/(2)) . The phase difference between these after 1 second is

Two simple harmonic motion, are represented by the equations y _(1) = 10 sin ( 3 pi t + (pi)/(3)) y _(2) = 5 ( sin 3 pi t + sqrt3 cos 3 pi t ) Ratio of amplitude of y _(1) to y _(2) = x :1. The value of x is __________