ABC is a triangle and EF is any straight line parallel to BC meeting AC, AB in E,F respectively. If `BR and CQ` be drawn parallel to AC, AB respectively to meet EF in R and Q respectively,prove that `DeltaARB =DeltaACQ.`

In triangleABC , a straight line parallel to BC intersects AB and AC at P and Q respectively. If AB = 3PB, then PQ : BC =

In triangle ABC, D and E are points on side AB such that AD = DE = EB. Through D and E, lines are drawn parallel to BC which meet side AC at points F and G respectively. Through F and Glines are drawn parallel to AB which meet side BC at points M and N respectively. Prove that : BM = MN = NC.

ABC is a triangle A line is drawn parallel to BC to meet AB and AC in D and E respectively. Prove that the median through A bisects DE.

ABC is a triangle A line is drawn parallel to BC to meet AB and AC in D and E respectively. Prove that the median through A bisects DE.

In triangle ABC, a line parallel to BC meets AB and AC at D and E respectively. If AE=4.5, cm, AD/DB =2/5.What is the length of EC ?

Draw any triangle ABC. Bisect side AB at D. Through D, draw a line parallel to BC, meeting AC in E. Measure AE and EC .

A line parallel to BC of a triangle ABC, intersects AB and AC at D and E respectively. Prove that (AD//DB) =( AE//EC) .

In figure X and Y are the mid-points of AC and AB respectively, QP || BC and CYQ and BXP are straight lines. Prove that ar (DeltaABP) = ar (DeltaACQ) .

In figure X and Y are the mid-points of AC and AB respectively, QP || BC and CYQ and BXP are straight lines. Prove that ar (DeltaABP) = ar (DeltaACQ) .