An electron is moving with speed `2xx10^5 m//s` along the positive x-direction in the presence of magnetic induction `vecB = (hat i + 4 hat j - 3 hat k) T`. The magnitude of the force experienced by the electron in `N ( e = 1.6xx 10^(-19) C) ( vec F = q ( vec v xx vec B))`

Find the magnitude of vec a give by vec a=( hat i+2 hat j-2 hat k)xx(- hat i+3 hat k)

An electron enters an electric field having intensity vec(E )= (3 hat(i) + 6hat(j) +2 hat(k)) Vm^(-1) and magnetic field having induction vec(B)= (2 hat(i) + 3hat(j)) T with a velocity vec(V)= (2 hat(i) + 3hat(j)) ms^(-1) . The magnitude of the force acting on the electron is (Given e= -1.6 xx 10^(-19)C )

If vec A=4 hat i+6 hat j and vec B=3 hat j+4 hat k , then find the component of vec A along vecB

If vec A = hat i + 3 hat j + 2 hat K and vec B = 3 hat i + hat j + 2 hat k , then find the vector product vec A xx vec B .

Find |vec a xx vec b| if vec a = hat i -7 hat j + 7 hat k and vec b = 3 hat i - 2 hat j + 2 hat k .

An electron moves with a velocity vec = (3 xx 10^6 hat i +4 xx 10^(+6) hat j) m/s through a magnetic field of strength B= (0.03 hat(i) + 0.15 hat (j)) T. Calculate the force on the electron.

If vec A = 2 hat i + 2 hat j - hat k and vec B = hat i + 4 hat j- 3 hat k then find (a) vec A * vec B (b) vec A xx vec B

Find |vec a xx vec b| if vec a = 2 hat i - hat j + 3 hat k and vec b = 3 hat i - 5 hat j + 2 hat k .

If vec (a) = 2 hat (i) - hat (j ) and vec (b) = 3 hat (i) - 2 hat (j) + 4 hat (k) , then the value of vec (a) xx vec (b) is -