In the six cornered figure, AC,AD and AE are joined. Find` /_FAB+/_ABC+/_BCD+/_CDE+/_DEF+/_EFA`

In the six cornered figure, (fig.20), AC,AD and AE are joined. Find /_F A B+/_A B C+/_B C D+/_C D E+/_D E F+/_E F Adot

In the six cornered figure, (fig.20), AC,AD and AE are joined. Find /_F A B+/_A B C+/_B C D+/_C D E+/_D E F+/_E F Adot

In five cornered fig.18,AD,AC are joined.Find /_EAB+/_BAC+/_BCD+/_CDE+/_DEA

In the above figure, bar(AB)||bar(DE) and ACE is a straight line . I f /_ABC =30^(@) and /_CDE =20^(@) , then find /_BCD .

In the given figure, AB = AC and AD = AE. Prove that: BD = CE

In the given figure BC||DE and AD=DB=3.4 and AC=14. So, find AE and EC.

In the given figure DO and CO are the bisectors of /_ADC and /_BCD respectively. If /_ADC=/_BCD=60^(@) and /_DAB=100^(@) find /_DOC and /_ABC

In the given figure BC|\|DE and AD=DB=3.4 and AC=14 . So find AE and EC.

In the adjoining figure, AP ⊥ BC ,AD||BC ,then find A(Delta ABC):A(Delta BCD) .

in the adjjoining figure,AB=AC and AD=AE . Prove that 1./_ADB=/_AEC2Delta ABD~=/_ACE3.BE=DC