If `(1 + by)^n = (1+ 8y + 24y^2 +....)` where `n in N` then the value of b and n are respectively-

If n(x) = 4, n (Y) = 3 and n(X xx Y xx Z) = 24 , then the value of n(Z) is

If in the expansion of (1+px)^(n),n in N , the coefficial of x and x^(2) are 8 and 24, than the values of n and p are:

If in the expansion of (1 + ax)^(n),n in N, the coefficient of x and x^(2) are 8 and 24 respectively, then

If in the expansion of (1 + ax)^(n),n in N, the coefficient of x and x^(2) are 8 and 24 respectively, then

Let A and B be two sets such that n(A) = 3 a n d n(B) = 2 . If (x , 1), (y , 2), (z , 1) are in A xx B. find A and B. where x, y and z are distinct elements.

For the natural number m, n, if ( 1- y ) ^(m) (1 + y) ^( n) =1 + a _(1) y + a _(2) y ^(2) + ...+ a _( m + n) y ^( m +n) and a _(1) = a _(2) = 10, then the value of (m+n) is equal to :

If X = {4 ^(n)-2n-1: n in N} and Y={9(n -1) : n in N}, then Xnn Y=

If X = {4 ^(n)-2n-1: n in N} and Y={9(n -1) : n in N}, then Xnn Y=