[" If a function "y=f(x)" satisfies the "],[" differential equation "],[f(x)*sin2x-cos x+(1+sin^(2)x)f'(x)=0],[" with initial condition "y(0)=0" ,then the "],[" value of "f((pi)/(6))" is equal to "]

A function y=f (x) satisfies the differential equation f(x) sin 2x-cos x+(1 + sin^2x)f'(x)= 0 with initial condition y(0)=0 . The value of f(pi/6) is equal to (A) 1/5 (B) 3/5 (C) 4/5 (D) 2/5

A function y=f (x) satisfies the differential equation f(x) sin 2x-cos x+(1 + sin^2x)f'(x)= 0 with initial condition y(0)=0 . The value of f(pi/6) is equal to (A) 1/5 (B) 3/5 (C) 4/5 (D) 2/5

A function y=f(x) satisfies the differential equation f(x)sin2x-cos x+(1+sin^(2)x)f'(x)=0 with initial condition y(0)=0. The value of f((pi)/(6)) is equal to (A) (1)/(5)(B)(3)/(5)(C)(4)/(5)(D)(2)/(5)

A function y-f (x) satisfies the differential equation f (x) sin 2x - cos x+(1+ sin ^(2)x) f'(x) =0 with f (0) =0. The value of f ((pi)/(6)) equals to :

A function y=f(x) satisfying the differential (dy)/(dx)*sin x-y cos x+(sin^(2)x)/(x^(2))=0 such that y rarr0 as x rarr oo then :

A function y = f(x) satisfies the differential (dy)/(dx)*sin x -y cos x+sin^2 x/x^2=0 such that y -> 0 as x -> oo . Then:

If f'(x)=3x^(2)sin x-x cos x x!=0 f(0)=0 then the value of f((1)/(pi)) is

If f'(x)=3x^(2)sin x-x cos x ,x!=0 f(0)=0 then the value of f((1)/(pi)) is