[" 2"],[" A particle of charge "q" and mass "m" starts moving from the origin under the action of an electric field "],[vec E=E_(0)hat t" and magnetic field "vec B=B_(0)hat i" with a velocity "vec v=v_(0)hat j" .The speed of the particle will "],[" become "2v_(0)" after a time "]

A particle of charge q and mass m starts moving from the origin under the action of an electric field vec E = E_0 hat i and vec B = B_0 hat i with a velocity vec v = v_0 hat j . The speed of the particle will become 2v_0 after a time.

A particle of charge q and mass m starts moving from the origin under the action of an electric field vec E = E_0 hat i and vec B = B_0 hat i with a velocity vec v = v_0 hat j . The speed of the particle will become 2v_0 after a time.

A particle of charge q and mass m starts moving from the origin under the action of an electric field vec E = E_0 hat i and vec B = B_0 hat i with a velocity vec v = v_0 hat j . The speed of the particle will become 2v_0 after a time.

A particle of charge q and mass m starts moving from the origin under the action of an electric field vec E = E_0 hat i and vec B = B_0 hat i with a velocity vec v = v_0 hat j . The speed of the particle will become 2v_0 after a time.

A particle of charge q and mass m starts moving from the origin under the action of an electric field vecE=E_0 hat i and vec B=B_0 hat i with velocity vec v=v_0 hat j . The speed of the particle will become 2v_0 after a time

The electric field acts positive x -axis. A charged particle of charge q and mass m is released from origin and moves with velocity vec(v)=v_(0)hatj under the action of electric field and magnetic field, vec(B)=B_(0)hati . The velocity of particle becomes 2v_(0) after time (sqrt(3)mv_(0))/(sqrt(2)qE_(0)) . find the electric field:

A particle having mass m and charge q is released from the origin in a region in which electric field and megnetic field are given by vec(B) = -B_(0)hat(j) and vec(E) = vec(E)_(0)hat(k) . Find the speed of the particle as a function of its z -coordinate.