A capacitor of capacitance `3muF` is first charged by connecting it across a 10 V battery by closing key `K_(1)`. Then it is allowed to get discharged through `2 Omega` and `4 Omega` resistors by closing the key `K_(2)`. The total energy dissipated in the `4 Omega` resistor is equal to

A capacitor of capacitance 3 mu F is first charged by connecting it across a 10 V battery by closing key K_(1) , then it is allowed to get discharged through 2 Omega and 4 Omega resistors by opening K_(1) and closing the key K_(2) . The total energy dissipated in the 2 Omega resistor is equal to

Power dissipated across the 8 Omega resistor in the circuit shown here is 2 W. The power dissipated in the 3Omega resistor is

In given circuit initially switch S_(1) is closed for long time and then opened and now S_(2) is closed. The total energy dissipated in 4 Omega resistor is equal to :-

Power dissipated across the 8 Omega resistor in the circuit shown here is 2 w. The power U dissipated in watt units across the 3Omega resistor is .

In an electrical circuit, two resistors of 2 Omega and 4 Omega respectively are connected in series to a 6 V battery. The heat dissipated by the 4 Omega resistor in 5 s will be :

In an electrical circuit, two resistors of 2 Omega and 4 Omega respectively are connected in series to a 6 V battery. The heat dissipated by the 4 Omega resistor in 5 s will be :

A 5 V battery with internal resistance 1 Omega and a 2 V battery with internal resistance 0.5 Omega are connected to a 3 Omega resistor as shown in the figure.The current in the 3 Omega resistor is

Two resistor 400 Omega and 800 Omega connected in series across a 6 V battery . Reading of Voltmeter of 10 k Omega across 400 Omega resistor is close to :