" 5."(sqrt(5)-sqrt(2))(sqrt(5)+sqrt(2))" ri "24i&" 34"2414" i."

Solve (sqrt(5)+sqrt(3)i)/(sqrt(5)+sqrt(3)i)

(5+sqrt(2)i)/(1-2sqrt(i))

((3)/(sqrt(5))x-5)+i2sqrt(5)y=sqrt(2)

(sqrt(5+2i^(2))+sqrt(5-2i))/(sqrt(5+2i)-sqrt(5-2i))

(sqrt(5+12i)+sqrt(5-12i))/(sqrt(5+12i)-sqrt(5-12i))

(sqrt(5+12i)+sqrt(5-12i))/(sqrt(5+12i)-sqrt(5-12i))=

(sqrt5 + i sqrt3)(-2 + i)

The expression ((5sqrt(3) + sqrt(50))(5-sqrt(24)))/(sqrt(75) - 5sqrt(2)) simplifies to

[(sqrt(5)+i/2)(sqrt(5)-i2)]-:(6+i5)

Simplify by raationalising the denominator. (i) (7sqrt(3) - 5sqrt(2))/(sqrt(48) + sqrt(18)) (ii) (2sqrt(6) -sqrt(5))/(3sqrt(5)-2sqrt(6))