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50 mL of each gas A and of gas B takes 1...

`50 mL` of each gas `A` and of gas `B` takes `150 and 200` seconds respectively for effusing through a pin hole under the similar conditon. If molecular mass of gas `B` is `36`, then the molecular mass of gas `A` will be

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50mL of each gas A and of gas B takes 150 and 200 seconds respectively for effusing through a pin hole under the similar conditions. If molecular mass of gas B is 36, the molecular mass of gas A will be :

50 mL of each gas A and of gas B takes 150 and 200 seconds respectively for effusing through a pin hole under the similar conditions. If molecular mass of gas A is 36, the molecular mass of gas B will be

50 mL of each gas A and gas B take 150 and 200 s respectively for effusing through a pin hole under the similar conditions, if molecular mass of gas B is 36, the molecular mass of gas A will be

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Sum of molecular mass of gas (A+C) is :

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Rate of diffusion of gas A is (1)/(2) that of gas 'B'. If molecular mass of gas A is 16 than calculate molecular mass of gas 'B'.

Rate of diffusion of gas A is (1)/(2) that of gas 'B'. If molecular mass of gas A is 16 than calculate molecular mass of gas 'B'.