`(-sqrt3+ sqrt-2) (2 sqrt3 -i)` को `a + ib` के रूप में व्यक्त करो।

Explanation

`(-sqrt3 + sqrt-2) (2 sqrt3 -i)`
`= (-sqrt3 + sqrt2i) (2 sqrt3 -i)`
`= (-sqrt3) (2 sqrt3) + (sqrt2i) (2 sqrt3) + sqrt3i - sqrt2i^(2)`
`= -6 +2 sqrt6i + sqrt3i + sqrt2`
`= (-6 + sqrt2) + sqrt3 (1 + 2 sqrt2)i`