यदि `3sinA=4cosA,` तो
`(i)sinA" "(ii)cosA`
के मान ज्ञात कीजिए।

Explanation

`3sinA=4cosA`
`implies(sinA)/(cosA)=4/3`
`impliestanA=4/3`
`impliesP/B=4/3`
यदि `P=4x,B=3x` तो
`H^(2)=p^(2)+B^(2)=(4x)^(2)+(3x)^(2)=16x^(2)+9x^(2)=25x^(2)`
`H=5x`

`sinA=P/H=(4x)/(5x)=4/5`
`cosA=B/H=(3x)/(5x)=3/5`
`tan A=4/3` और
`sec A=H/B=(5x)/(3x)=5/3`
`impliestan^(2)A-sec^(2)A=((4)/(3))^(2)-((5)/(3))^(2)=19/9-25/9=(-9)/(9)=-1.`