13.sin^(2)x+2cos y+xy=0

If sin^(2)x+2cos y+xy=0 then (dy)/(dx)=

sin^(2)y + cos xy = k

Find dy/dx : sin x + 2 cos^2 y+xy=0

If xe^(xy)=y+sin^(2)x then at x=0(dy)/(dx)=

If y=Asin^2x+Bcos^2x then prove that sin2xy_2-2cos2xy_1=0

If a = x cos ^ (2) a + y sin ^ (2) A then (xa) (ya) + (xy) ^ (2) sin ^ (2) A cos ^ (2) A =

Solution of differential equation (2x cos y + y ^ (2) cos x) dx (2y sin xx ^ (2) sin y) dx = 0 is (a) x ^ (2) cos y + y ^ (2) sin x = C (b) x cos yy sin x = C (c) x ^ (2) cos ^ (2) y + y ^ (2) sin ^ (2) x = C (d) x cos y + y sin x = C

cos (x + y), sin (x + y), - cos (x + y) sin (xy), cos (xy), sin (xy) sin2x, 0, sin2y] | = sin2 (x + y)

Solve: {(xy)cos(xy)+sin(xy)}dx+x^2cos(xy)dy=0