The function `f: Rvec[-1/2,1/2]` defined as `f(x)=x/(1+x^2),` is : Surjective but not injective (2) Neither injective not surjective Invertible (4) Injective but not surjective

Show that f: RvecR defined by f(x)=(x-1)(x-2)(x-3) is surjective but not injective.

Let A={x:xepsilonR-{1}}f is defined from ArarrR as f(x)=(2x)/(x-1) then f(x) is (a) Surjective but nor injective (b) injective but nor surjective (c) neither injective surjective (d) injective

Let A={x:xepsilonR-{1}}f is defined from ArarrR as f(x)=(2x)/(x-1) then f(x) is (a) Surjective but nor injective (b) injective but nor surjective (c) neither injective surjective (d) injective

Let R be the set of real numbers.If f:R rarr R is a function defined by f(x)=x^(2), then f is injective but not surjective surjective but not injective but not surjective surjective but not but not surjective (b) surjective but not injective (c) bijective (d) non of these

Let R be the set of real numbers. If f:R->R is a function defined by f(x)=x^2, then f is injective but not surjective surjective but not injective bijective none of these (a) injective but not surjective (b) surjective but not injective (c) bijective (d) non of these

Show that f: R->R defined by f(x)=(x-1)(x-2)(x-3) is surjective but not injective.

Show that f: R->R defined by f(x)=(x-1)(x-2)(x-3) is surjective but not injective.

Show that f: R->R defined by f(x)=(x-1)(x-2)(x-3) is surjective but not injective.

Show that f: R->R defined by f(x)=(x-1)(x-2)(x-3) is surjective but not injective.

Let A={x:x varepsilon R-}f is defined from A rarr R as f(x)=(2x)/(x-1) then f(x) is (a) Surjective but nor injective (b) injective but nor surjective (c) neither injective surjective (d) injective