if f(x)=`|1-x|,1lexle2,and g(x)=f(x)+bsin((pix)/2),`then which of the following is correct

Consider f(x) = |1-x |, 1

Let f(x)={{:(-2",",-3lexle0),(x-2",",0ltxle3):}andg(x)=f(|x|)+|f(x)| Which of the following statement is correct ? g(x) is differentiable at x=0 g(x) is differentiable at x=2

Let f(x)={{:(-2",",-3lexle0),(x-2",",0ltxle3):}andg(x)=f(|x|)+|f(x)| Which of the following statement is/are correct? 1. g(x) is differentiable x=0. g(x) is differentiable at x=2. Select the correct aswer using the code given below:

Consider the function f(x)=f(x)={{:(x-1",",-1lexle0),(x^(2)",", 0lexle1):} and " "g(x)=sinx. If h_(1)(x)=f(|g(x)|) " and "h_(2)(x)=|f(g(x))|. Which of the following is not true about h_(2)(x) ?