[" 2n boys are randomly divided into two subgroups containing n boys each.The probability that the two "],[" tallest boys are in different groups is "]

2n boys are randomly divided into two subgroups containint n boys each. The probability that the two tallest boys are in different groups is a. n//(2n-1) b. (n-1)//(2n-1) c. (n-1)//4n^2 d. none of these

2n boys are randomly divided into two subgroups containint n boys each. The probability that eh two tallest boys are in different groups is n//(2n-1) b. (n-1)//(2n-1) c. (n-1)//4n^2 d. none of these

24 boys are divided randomly into two equal groups. The probability that two tallest boys are in the different groups is

40 boys of a class are divided into two equal group. Find the probability that the 2 tallest boys are in two different groups.

If 15 boys of different ages are distributed into 3 groups of 4,5, and 6 boys randomly then the probability that three youngest boys are in different groups is

10 boys and 2 girls are divided into 3 groups of 4 each.The probability that the girls will be in different groups is

6 boys and 6 girls are randomly divided into two equal groups. Find the probability that each group contains same number of boys and girls.

A group of 2n boys and 2n girls is randomly divided into two equal groups.The probability that each group contains the same number of boys and girls is (A) 1/2 (B) 1/n (c) 1/2n (D) None of these

The number of ways in which 10 boys can be divied into 2 groups of 5, such that two tallest boys are in two different groups, is equal to