In Young's double-slit experiment using `lambda=6000 Å`, distance between the screen and the source is 1m. If the fringe-width on the screen is 0.06 cm, the distance between the two coherent sources is

In Young's double slit experiment, the distance between sources is 1 mm and distance between the screen and source is 1 m . If the fringe width on the screen is 0.06 cm , then lambda =

In a Young’s double slit experiment, the slit separation is 0.2 cm , the distance between the screen and slit is 1 m . Wavelength of the light used is 5000 Å . The distance between two consecutive dark fringes (in mm ) is

In Young's double slit experiment, the distance between the two slits is 0.1 mm, the distance between the screen and the slit is 100 cm. if the width of the fringe is 5 mm, then the wavelength of monochromatic light used is

In Young's double slit experiment if distance between the two sources is increased how will the fringe width be changed?

In young's double slit experiment, if the distance between the slits is halved and the distance between the slits and the screen is doubled, the fringe width becomes

In Young's double slit experiment, the distance between the two slits is 0.1 mm and the wavelength of light used is 4 xx 10^(-7) m . If the width of the fringe on the screen is 4 mm , the distance between screen and slit is

In Young's double slit experiment,the sepaation between the slit is halved and distance between the slits and screen is doubled.The fringe width is