Let the base of a triangle lie along the line `x = a` and be of length `a.` The area of this triangle is `a2`, if the vertex lies on the line

Let the base of a triangle lie along the line x = a and be of length 2a. The area of this triangles is a^(2) , if the vertex lies on the line

Let the base of a triangle lie along the line x = a and be of length 2a. The area of this triangles is a^(2) , if the vertex lies on the line

Let the base of a triangle lie along the line x = a and be of length a. The area of this triangles is a^(2) , if the vertex lies on the line

Let the base of a triangle lie along the line x = a and be of length a. The area of this triangles is a^(2) , if the vertex lies on the line

The base of a triangle lies along the line x=a and is of length a. The area of the triangle is a^2. The locus of the third vertex is

The base of a triangle lies along x= 1and is of length 1. The area of triangle is 1. The locus of vertex is

The base of a triangle lies along x=5 and is of length 1 .The area of triangle is 1 . The locus of vertex is

The base of an equilateral triangle is along the line given by 3x+4y=9 . If a vertex of the triangle is (1,2) then length of a side of the triangle is

One side of length 3a of a triangle of area a^2 square units lies on the line x = a. Then one of the lines on which the third vertex lies, is :