" Q38.In the figure,"/_BED=/_BDE" and "E" is the mid-point of "BC" .Prove that "(AF)/(CF)=(AD)/(BE)

In the figure,/_BED=/_BDE and E is the middle point of BC. Prove that (AF)/(CF)=(AD)/(BE)

AD BE and CF are the medians of a Delta ABC .Prove that 2(AD+BE+CF)<3(AB+BC+CA)<4(AD+BE+CF)

In a ABC,E is the mid-point of median AD Show that ar(BED)=(1)/(4) ar (ABC)

In ABC,AD is the median through A and E is the mid-point of AD.BE produced meets AC in F (Figure).Prove that AF=(1)/(3)AC .

In the figure, M is the mid-point of [AB] and N is the mid-point of [CD] and O is the mid-point of [MN]. Prove that : vec(BC)+vec(AD)=2vec(MN) .

In the given figure ABCD is a trapezium, P is the mid-point of side AD and PR||AB||DC . Prove that R is the mid-point of side BC

in figure,M is the mid-point of AB and N is the mid-point of BC(1) if AB=BC, prove that AM=NC

in figure,M is the mid-point of AB and N is the mid-point of BC(1) if AB=BC, prove that AM=NC

In the given figure, ABCD and ABEF are parallelograms. If O is the mid-point of BC, show that : DC = CF = FE.

In the fig. AD is a median of triangle ABC and E is the mid point of AD, also BE meets AC in F. prove that AF=1/3AC