`(1)/("log"_(2)n) + (1)/("log"_(3)n) + (1)/("log"_(4)n) + … + (1)/("log"_(43)n)=`

If (1)/("log"_(2)a) + (1)/("log"_(4)a) + (1)/("log"_(8)a) + (1)/("log"_(16)a) + …. + (1)/("log"_(2^(n))a) = (n(n+1)/(lambda)) then lambda equals

If (1)/("log"_(2)a) + (1)/("log"_(4)a) + (1)/("log"_(8)a) + (1)/("log"_(16)a) + …. + (1)/("log"_(2^(n))a) = (n(n+1)/(lambda)) then lambda equals

In n = 10!, then what is the value of the following? (1)/(log_(2)n) +(1)/(log_(3)n) +(1)/(log_(4)n)+…..+ (1)/(log_(10)n)

If n>1, then prove that(1)/(log_(2)n)+(1)/(log_(3)n)+...+(1)/(log_(53)n)=(1)/(log_(53)n)

If n=|__2002, evaluate (1)/(log_(2)n)+(1)/(log_(3)n)+(1)/(log_(4)n)+......+(1)/(log_(2002)n)

The value of (1)/(log_(3)n)+(1)/(log_(4)n) + (1)/(log_(5)n) + ... + (1)/(log_(8)n) is ______.

If n>1 then prove that (1)/(log_(2)n)+(1)/(log_(3)n)+............+((1)/(log_(53)n)=(1)/(log_(53!)n)

If n=(2017)! , then what is (1)/(log_(2)n)+(1)/(log_(3)n)+(1)/(log_(4)n)+....+(1)/(log_(2017)n) equal to?