" (iii) "(5y+(15)/(y))(25y^(2)-75+(225)/(y^(2)))

If x=-2 and y=1, by using an identity find the value: (5y+(15)/(y))(25y^(2)-75+(225)/(y^(2)))

If y=1, by using an identity find the value: (5y+(15)/y)(25 y^2-75+(225)/(y^2))

Find the products: ((3)/(x)-(5)/(y))((9)/(x^(2))+(25)/(y^(2))+(15)/(xy))

sqrt(125)y^(2)+sqrt(25y^(4))by5y^(2)

{:("Column" A ,, "Column" B), (225x^(2) - 625 y^(2) = ,, (a) 25(x-2) (x-2)), (x^(2) - x - y - y^(2) = ,, (b) 25(3x- 5y) (3x + 5y)), (x^(2) - x - y^(2) + y = ,, (x + y) (x - y- 1)), (25x^(2) - 100 x + 100 = ,, (d) (x - y) (x + y -1)), (,,(e) (x + y) (x + y - 1)):}

Find the products: (3/x-5/y)(9/(x^2)+(25)/(y^2)+(15)/(x y))

(9x^(2)-25y^(2)+60y-36)/((3x+5y-6))

The equation of the ellipse whose vertices are (9,2),(-1,2) and the distance between the foci is 8 unit is (A)9(x-3)^(2)+25(y-4)^(2)=225(B)9(x+3)^(2)+25(y+4)^(2)=225(C)9(x-4)^(2)+25(y-3)^(2)=225(D)9(x+4)^(2)+25(y+3)^(2)=225