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[" 2.The magnetic moment of "K(3)(Fe(CN)...

[" 2.The magnetic moment of "K_(3)(Fe(CN)_(6)]" is found to be "],[1.7BM" .How many unpaired electron (s) is/are "],[" present per molecule "],[[" (1) "1," (2) "2],[" (3) "3," (4) "4]]

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The magnetic moment of K_(3)[Fe(CN)_(6)] is found to be 1.7 B.M. how many unpaired electron (s) is/are present per molecule

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