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s^2tan(A/2)tan(B/2)tan(C/2)...

`s^2tan(A/2)tan(B/2)tan(C/2)`

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In DeltaABC , prove that: s^(2).tan(A/2)tan(B/2)tan(C/2)=Delta

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v) tan(A/2)tan(B/2)+tan(B/2)tan(C/2)+tan(C/2)tan(A/2)=1

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(tan(B/2)-tan(C/2))/(tan(B/2)+tan(C/2))