Focal length of a thin lens in air is 10cm. Now, medium on one side of the lens is replaced by a medium of refractive inidex `mu=2`. The radius of curvature of the surface of lens, in contact with the medium, is 20cm. Find the new focal length.

Focal length of a thin lens in air, is 10 cm. Now medium on one side of the lens is replaced by a medium of refractive index mu = 2 . The radius of curvature of surface of leng, in contact with the medium, is 20 cm. Find the point on principal axis where parallel rays incident on lens from air parallel to axis will converge.

A planocovex lens is made of a material of refractive in mu=1.5 The radius of curvature of curved surface of the lens is 20.cm. If its plane surface3 is silvered, the focal length of the silvered lens will be

A planocovex lens is made of a material of refractive in mu=1.5 The radius of curvature of curved surface of the lens is 20.cm. If its plane surface3 is silvered, the focal length of the silvered lens will be

Focal length of convex lens in air is 16 cm ( mu_glass = 1.5 ). Now the lens is submerged in liquid of refractive index 1.42. Find the ratio of focal length in medium to focal length in air has closest value

A convex lens of focal length .f is placed in a medium of refractive index equal to that of lens What happens to its focal length?

Focal length of convex lens in air is 16 cm ( mu_(glass) = 1.5 ). Now the lens is submerged in liquid of refractive index 1.42. Find the ratio of focal length in medium to focal length in air has closest value

Focal length of convex lens in air is 16 cm ( mu_(glass) = 1.5 ). Now the lens is submerged in liquid of refractive index 1.42. Find the ratio of focal length in medium to focal length in air has closest value

The focal lengtli of a equiconvex lens is 2/3 times the radius of curvature of the surface. What is the refractive index of the medium?