A parallel plate capacitor having capacitance 12pF is charged bya battery to a potential difference of 10V between its plates. The charging battery is now disonnected and a porcelain slab of dielectric constant 6.5 is slipped between the plates. The work done by the capacitor on the slab is

A parallel plate capacitor whose capacitance C is 13.5 pF is charged by a battery to a potential difference V=12.5V between its plates. The charging battery is now disconnected, and a porcelain slab (k=6.50) is slipped between the plates. (a) What is the potential energy of the capacitor before the slab is inserted? (b) What is the potential energy of the capacitor slab device after the slab is inserted?

Figure shows a parallel plate capacitor with plate area A and plate separation d . A potential difference is being applied between the plates. The battery is then disconnected and a dielectric slab of dieletric constant K is placed in between the plates of the capacitor as shown. The electric field in the gaps between the plates and the electric slab will be

A parallel plate capacitor of capacitance C_(0) is charged with a charge Q_(0) to a potential difference V_(0) and the battery is then disconnected Now a dielectric slab of dielectric constant k is inserted between the plates ofcapacitor. The dimensions of the slab are such that it completely fills the space between the plates, then :

While a capacitor remains connected to a battery, a dielectric slab is slipped between the plates. Then

A dielectric slab is placed between the plates of a parallel plate capacitor. Its capacitance

A parallel - plate capacitor of plate area A and plate separation d is charged to a potential difference V and then the battery is disconnected . A slab of dielectric constant K is then inserted between the plate of the capacitor so as to fill the space between the plate .Find the work done on the system in the process of inserting the slab.

A parallel - plate capacitor of plate area A and plate separation d is charged to a potential difference V and then the battery is disconnected . A slab of dielectric constant K is then inserted between the plate of the capacitor so as to fill the space between the plate .Find the work done on the system in the process of inserting the slab.

A parallel - plate capacitor of plate area A and plate separation d is charged to a potential difference V and then the battery is disconnected . A slab of dielectric constant K is then inserted between the plate of the capacitor so as to fill the space between the plate .Find the work done on the system in the process of inserting the slab.