(1)/(a+b+x)=(1)/(a)+(1)/(b)+(1)/(x),[x!=0,-((a+b)])/(0)

Long-answer type questions (L.A.) (1)/(a+b+x)=(1)/(a)+(1)/(b)+(1)/(x){xne0,-(a+b)}

Solve: (1)/((a+b+x))=(1)/(a)+(1)/(b)+(1)/(x),[xne0,xne-(a+b)].

Solve (1)/(a+b+x)=(1)/(a)+(1)/(b)+(1)/(x),a+b!=0

Solve the following quadratic equation by factorization method (1)/(a+b+x)=(1)/(a)+(1)/(b)+(1)/(x),a+b!=0

Solve the following quadratic equations by factorization methd: (1)/(a+b+x)=(1)/(a)+(1)/(b)+(1)/(x),a+b!=0

Solve for x : (1)/(a + b + x) = (1)/(a) + (1)/(b) + (1)/(x) , a ne b ne 0 , x ne 0 , x ne -(a + b)

Solve for 'x' : (1)/(a+b+x)=(1)/(a)+(1)/(b)+(1)/(x) " " a != 0, b!=0, x !=0

Solve: 1/(a+b+x) = 1/a+1/b+1/x,x!=0,-(a+b)

Long-answer type questions (L.A.) (1)/(x)-(1)/(x+b)=(1)/(a)-(1)/(a+b)(xne0,-b)

Solve : 1/(a+b+x)=1/a+1/b+1/x[ x ne 0, -(a+b)]