In `YDSE` when slab of thickness `t` and refractive index `mu` is placed in front of one slit then central maxima shifts by one fringe width. Find out `t` in terms of `lambda` and `mu`.

In YDSE , slab of thickness t and refractive index mu is placed in front of any slit. Then displacement of central maximu is terms of fringe width when light of wavelength lamda is incident on system is

In YDSE , slab of thickness t and refractive index mu is placed in front of any slit. Then displacement of central maximu is terms of fringe width when light of wavelength lamda is incident on system is

The figure shows a Young's double slit experimental setup. It is observed that when a thin transparent sheet of thickness t and refractive index mu is put front of one of the slits, the central maximum gets shifted by a distance equal to n fringe widths. If the wavelength of light used is lambda , t will be :

In Young's double-slit experiment, let A and B be the two slit. A thin film of thickness t and refractive index mu is placed in front of A. Let beta = fringe width. Then the central maxima will shift

In Young's double-slit experiment, let A and B be the two slit. A thin film of thickness t and refractive index mu is placed in front of A. Let beta = fringe width. Then the central maxima will shift

In a Young's double slit experiment let A and B be the two slits. A thin plate of thickness t and refractive index mu is placed in front of A. Let beta be the fringe width. The central maximum will shift

In a YDSE experiment, the distance between the slits & the screen is 100 cm . For a certain distance between the slits, an interference pattern is observed on the screen with the fringe width 0.25 mm . When the distance between the slits is increased by Deltad=1.2 mm, the fringe width decreased to n=2//3 of the original value. In the final position, a thin glass plate of refractive index 1.5 is kept in front of one of the slits & the shift of central maximum is observed to be 20 fringe width. Find the thickness of the plate & wavelength of the incident light.

In Young’s double slit experiment a transparent sheet of thickness t and refractive index mu is placed in front of one of the slits and the central fringe moves away from the central line. It was found that when temperature was raised by Deltatheta the central fringe was back on the central line (at C). It is known that temperature coefficient of linear expan- sion of the material of the transparent sheet is alpha . A young scientist modeled that the refractive index of the material changes with temperature as Deltamu"= – gama Deltatheta . Find Deltatheta in terms of other given quantities. D and d are given and have usual meaning.

In a doulble slit experiment when a thin film of thickness t having refractive index mu is introduced in from of one of the slits, the maximum at the centre of the fringe pattern shifts by one width. The value of t is (lamda is the wavelength of the light used)